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Consider the following code snippet:
#include <iostream>
int main() {
    int* ptr = new int;
    *ptr = 10;
    std::cout << *ptr;
    delete ptr;
    return 0;
}
What will be the output of the above code?
  • a)
    10
  • b)
    0
  • c)
    Error
  • d)
    Undefined behavior
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Consider the following code snippet:#include <iostream>int main(...
Explanation:

Dynamic Memory Allocation:
- The code snippet uses dynamic memory allocation to allocate memory for an integer variable.

Assigning a Value:
- The value 10 is assigned to the memory location pointed to by the pointer 'ptr'.

Printing the Value:
- The value stored at the memory location pointed to by 'ptr' is printed using std::cout.

Deleting Allocated Memory:
- The memory allocated dynamically using 'new' is released using 'delete' to avoid memory leaks.
Therefore, the output of the code will be '10'. This is because the value stored at the memory location pointed to by 'ptr' is 10, and it is successfully printed before deleting the allocated memory.
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Community Answer
Consider the following code snippet:#include <iostream>int main(...
The 'new' keyword is used to allocate dynamic memory for an integer and returns a pointer to that memory. The value '10' is assigned to the memory location pointed to by 'ptr', so the output will be 10. However, it's important to note that the dynamically allocated memory should be freed using 'delete' to avoid memory leaks.
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Consider the following code snippet:#include <iostream>int main() { int* ptr = new int; *ptr = 10; std::cout << *ptr; delete ptr; return 0;}What will be the output of the above code?a)10b)0c)Errord)Undefined behaviorCorrect answer is option 'A'. Can you explain this answer?
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